Chapter 22 – Indices 2

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Cambridge IGCSE & O Level Mathematics
Chapter 22

Indices 2

Apply the index laws confidently to algebraic and numerical expressions, including zero, negative and fractional indices, and learn how to rewrite different bases before simplifying.

By the end of this chapter, you should be able to

  • multiply and divide algebraic expressions written in index form;
  • raise powers and coefficients to another power correctly;
  • use the zero-index rule and simplify expressions containing zero powers;
  • use negative and fractional indices accurately;
  • rewrite numbers with a common base before applying index laws;
  • solve simple exponential equations by expressing both sides with the same base.
1

Subtopic 1

Simplifying algebraic expressions using indices

Exam-ready method

Check the base before applying an index rule. Apply powers to every factor inside brackets; unlike powers cannot simply be added.

The same index laws used with numbers also apply to algebraic expressions. The key is to work with the coefficient and each base separately.

Multiply same base

\(a^m\times a^n=a^{m+n}\)

Add the indices.

Divide same base

\(a^m\div a^n=a^{m-n}\)

Subtract the indices.

Power of a power

\((a^n)^m=a^{nm}\)

Multiply the indices.

Zero index

\(a^0=1\)

For \(a\neq0\).

\(a^3\times a^5\)same base → add indices\(a^{3+5}=a^8\)
\(a^7\div a^2\)same base → subtract indices\(a^{7-2}=a^5\)
\((a^4)^3\)power of a power → multiply indices\(a^{12}\)
Worked example · Easy

Multiply coefficients and powers separately

Simplify \(3a^2\times4a^3\).

Multiply the coefficients:

\[3\times4=12\]

Add the indices because the base is the same:

\[a^2\times a^3=a^5\]

Answer: \(\boxed{12a^5}\).

Worked example · Easy

Division

Simplify \(\frac{18a^7}{6a^3}\).

\[18\div6=3\]\[a^7\div a^3=a^{7-3}=a^4\]

So the answer is \(\boxed{3a^4}\).

Worked example · Medium

Power of a product

Simplify \((2x^3)^4\).

Raise the coefficient and the power to the fourth power:

\[(2x^3)^4=2^4x^{12}=\boxed{16x^{12}}\]
Worked example · Medium

Several letters

Simplify \(\frac{12a^3b^2\times3a^2b^4}{2a^3b^2}\).

First simplify the numerator:

\[12a^3b^2\times3a^2b^4=36a^5b^6\]

Now divide:

\[\frac{36a^5b^6}{2a^3b^2}=18a^{5-3}b^{6-2}=\boxed{18a^2b^4}\]
Worked example · Medium

Zero index appears

Simplify \(\frac{15a^4b^3}{5a^4b}\).

\[\frac{15a^4b^3}{5a^4b}=3a^{4-4}b^{3-1}=3a^0b^2\]

Since \(a^0=1\):

\[\boxed{3b^2}\]
Do not apply index laws to addition
\(4a^2+3a^3\)

These are not like terms, so the expression cannot be simplified by adding the indices.

Worked example · Exam-style

Mixed operations

Simplify \(\frac{(3a^2b)^2\times2a}{6ab^2}\).

First expand the power:

\[(3a^2b)^2=9a^4b^2\]

Multiply the numerator:

\[9a^4b^2\times2a=18a^5b^2\]

Divide:

\[\frac{18a^5b^2}{6ab^2}=3a^4\]

Answer: \(\boxed{3a^4}\).

New worked example · Exam-style

Several rules together

Simplify \(\frac{(3a^2b)^2\,(2ab^3)}{6a^3b^2}\).

Worked method — show your mathematical steps and check restrictions or units.

\[(3a^2b)^2=9a^4b^2\]
\[\frac{9a^4b^2\cdot2ab^3}{6a^3b^2}=3a^{5-3}b^{5-2}\]
\[\boxed{3a^2b^3}\]

Try it yourself — from confidence to examination level

Attempt each question before opening its step-by-step solution.

1Multiply like bases · Build confidence[2 marks]

Simplify \(5p^3\times2p^4\).

Show Answer

Step-by-step solution

\[5\times2=10,\quad p^{3+4}=p^7\]
\[\boxed{10p^7}\]
2Power of a product · Develop skill[3 marks]

Simplify \((4x^2y)^2\).

Show Answer

Step-by-step solution

\[4^2=16,\quad (x^2)^2=x^4,\quad y^2=y^2\]
\[\boxed{16x^4y^2}\]
3Quotient of monomials · Exam-style[4 marks]

Simplify \(\frac{30a^7b^4}{5a^2b}\).

Show Answer

Step-by-step solution

\[\frac{30}{5}=6,\quad a^{7-2}=a^5,\quad b^{4-1}=b^3\]
\[\boxed{6a^5b^3}\]
4Recognise unlike terms · Exam challenge[5 marks]

Can \(3x^2+4x^3\) be combined into \(7x^5\)? Explain.

Show Answer

Step-by-step solution

\[\text{The terms have different powers of }x.\]
\[\boxed{3x^2+4x^3\text{ cannot be combined as like terms.}}\]
2

Subtopic 2

Using the laws of indices with numerical and algebraic expressions

Exam-ready method

Rewrite numbers as powers of the same base before combining; simplify zero, negative and fractional powers carefully, with nonzero-base restrictions where relevant.

Harder index questions combine several laws at once. It is often necessary to rewrite numbers with a common base before simplifying.

Negative index

\(a^{-n}=\frac1{a^n}\)

A negative index means reciprocal, not a negative value.

Fractional index

\(a^{1/n}=\sqrt[n]{a}\)

The denominator of the index indicates the root.

Combined fractional index

\(a^{m/n}=(\sqrt[n]{a})^m\)

Root and power can be applied in either order.

\(8^{3/4}\)rewrite 8 as \(2^3\)\((2^3)^{3/4}=2^{9/4}\)
\(2^3\times4^{3/2}\)rewrite \(4=2^2\)\(2^3\times(2^2)^{3/2}=2^6\)
\(9^n\times27^{2n}\)rewrite with base 3\(3^{2n}\times3^{6n}=3^{8n}\)
Worked example · Easy

Negative index

Write \(x^{-4}\) with a positive index.

\[x^{-4}=\boxed{\frac1{x^4}}\]
Worked example · Medium

Fractional index

Evaluate \(81^{3/4}\).

Take the fourth root first:

\[81^{1/4}=3\]

Then cube:

\[3^3=\boxed{27}\]
Worked example · Medium

Write as a single power

Simplify \(2^5\times4^{3/2}\).

Rewrite \(4\) as \(2^2\):

\[4^{3/2}=(2^2)^{3/2}=2^3\]

Then:

\[2^5\times2^3=\boxed{2^8}\]
Worked example · Medium

Algebraic powers with negative indices

Simplify \(4y^2\div2y^{-3}\).

\[4\div2=2\]\[y^2\div y^{-3}=y^{2-(-3)}=y^5\]

Answer: \(\boxed{2y^5}\).

Worked example · Exam-style

Different numerical bases

Write \(9^n\times27^{2n}\) as a single power of 3.

\[9^n=(3^2)^n=3^{2n}\]\[27^{2n}=(3^3)^{2n}=3^{6n}\]

Multiply same base:

\[3^{2n}\times3^{6n}=\boxed{3^{8n}}\]
\(2^x=32\)write 32 as a power of 2\(2^x=2^5\Rightarrow x=5\)
\(16^x=\frac14\)use base 2\(2^{4x}=2^{-2}\Rightarrow x=-\frac12\)
Worked example · Exam-style

Solve an exponential equation

Solve \(64^x=4\).

Write both sides with base 2:

\[64=2^6,\qquad4=2^2\]\[(2^6)^x=2^2\]\[2^{6x}=2^2\]

Equate the indices:

\[6x=2\Rightarrow\boxed{x=\frac13}\]
Worked example · Exam-style

Several laws together

Simplify \(\frac{6a^{-3}\times4a^2}{3a^{-2}}\).

Coefficients:

\[\frac{6\times4}{3}=8\]

Powers of \(a\):

\[a^{-3}a^2\div a^{-2}=a^{-3+2-(-2)}=a^1\]

So the expression simplifies to \(\boxed{8a}\).

High-grade habit

When different bases appear, first ask whether each number can be written as a power of the same base. Once the bases match, the index laws become much easier to apply.

New worked example · Exam-style

Combine fractional and negative indices

Write \(\frac{9^{1/2}\times3^{-2}}{3^{-1}}\) as a single power of 3.

Worked method — show your mathematical steps and check restrictions or units.

\[9^{1/2}=(3^2)^{1/2}=3^1\]
\[\frac{3^{1-2}}{3^{-1}}=3^{-1-(-1)}=3^0\]
\[\boxed{1}\]

Try it yourself — from confidence to examination level

Attempt each question before opening its step-by-step solution.

1Negative index · Build confidence[2 marks]

Write \(2^{-4}\) as a fraction.

Show Answer

Step-by-step solution

\[2^{-4}=\frac1{2^4}\]
\[\boxed{\frac1{16}}\]
2Fractional index · Develop skill[3 marks]

Evaluate \(81^{3/4}\).

Show Answer

Step-by-step solution

\[81^{1/4}=3\]
\[81^{3/4}=3^3=\boxed{27}\]
3Same numerical base · Exam-style[4 marks]

Simplify \(8^2\times4^{-1}\) as a power of 2.

Show Answer

Step-by-step solution

\[8^2=(2^3)^2=2^6,\quad4^{-1}=(2^2)^{-1}=2^{-2}\]
\[\boxed{2^4=16}\]
4Algebraic negative power · Exam challenge[5 marks]

Simplify \(\frac{x^{-2}y^3}{x^2y^{-1}}\) using positive indices.

Show Answer

Step-by-step solution

\[x^{-2-2}y^{3-(-1)}=x^{-4}y^4\]
\[\boxed{\frac{y^4}{x^4}},\quad x\ne0\]

Chapter 22 practice

Begin with the basic algebraic laws, then move to negative and fractional indices, common-base rewriting and simple exponential equations. Keep answers closed until you have tried each question.

A. Build confidence

1Multiply same base[2 marks]

Simplify \(5a^3\times2a^4\).

Show Answer

Method: Rewrite matching bases where useful, apply the relevant index law to each factor, and express the final answer in its simplest form.

\[5\times2=10\]\[a^3a^4=a^7\]

\(\boxed{10a^7}\)

2Divide same base[2 marks]

Simplify \(\frac{21x^8}{7x^3}\).

Show Answer

Method: Rewrite matching bases where useful, apply the relevant index law to each factor, and express the final answer in its simplest form.

\[21\div7=3,\qquad x^{8-3}=x^5\]

\(\boxed{3x^5}\)

3Power of a power[2 marks]

Simplify \((4y^2)^3\).

Show Answer

Method: Rewrite matching bases where useful, apply the relevant index law to each factor, and express the final answer in its simplest form.

\[4^3=64,\qquad(y^2)^3=y^6\]

\(\boxed{64y^6}\)

4Zero index[2 marks]

Simplify \(7p^0q^3\).

Show Answer

Method: Rewrite matching bases where useful, apply the relevant index law to each factor, and express the final answer in its simplest form.

Since \(p^0=1\):

\[7p^0q^3=\boxed{7q^3}\]

B. Negative and fractional indices

5Negative index[2 marks]

Write \(m^{-5}\) using only positive indices.

Show Answer

Method: Rewrite matching bases where useful, apply the relevant index law to each factor, and express the final answer in its simplest form.

\[\boxed{\frac1{m^5}}\]
6Fractional index[2 marks]

Evaluate \(64^{1/3}\).

Show Answer

Method: Rewrite matching bases where useful, apply the relevant index law to each factor, and express the final answer in its simplest form.

The cube root of 64 is 4.

\[\boxed{4}\]
7Fractional power[3 marks]

Evaluate \(32^{2/5}\).

Show Answer

Method: Rewrite matching bases where useful, apply the relevant index law to each factor, and express the final answer in its simplest form.

The fifth root of 32 is 2.

\[32^{2/5}=2^2=\boxed{4}\]
8Subtract a negative index[3 marks]

Simplify \(6x^4\div3x^{-2}\).

Show Answer

Method: Rewrite matching bases where useful, apply the relevant index law to each factor, and express the final answer in its simplest form.

\[6\div3=2\]\[x^{4-(-2)}=x^6\]

\(\boxed{2x^6}\)

C. Common-base reasoning

9Rewrite a base[3 marks]

Write \(2^4\times8^2\) as a single power of 2.

Show Answer

Method: Rewrite matching bases where useful, apply the relevant index law to each factor, and express the final answer in its simplest form.

\[8^2=(2^3)^2=2^6\]\[2^4\times2^6=\boxed{2^{10}}\]
10Variable exponent[3 marks]

Write \(4^n\times8^{2n}\) as a single power of 2.

Show Answer

Method: Rewrite matching bases where useful, apply the relevant index law to each factor, and express the final answer in its simplest form.

\[4^n=(2^2)^n=2^{2n}\]\[8^{2n}=(2^3)^{2n}=2^{6n}\]\[2^{2n}2^{6n}=\boxed{2^{8n}}\]
11Cannot be combined[2 marks]

Can \(3^4+3^2\) be written as \(3^6\)? Explain.

Show Answer

No. The rule \(a^m\times a^n=a^{m+n}\) applies to multiplication, not addition.

Indeed, \(3^4+3^2=81+9=90\), while \(3^6=729\).

12Mixed base and fractional index[4 marks]

Simplify \(2^3\times4^{5/2}\) as a single power of 2.

Show Answer

Method: Rewrite matching bases where useful, apply the relevant index law to each factor, and express the final answer in its simplest form.

\[4^{5/2}=(2^2)^{5/2}=2^5\]\[2^3\times2^5=\boxed{2^8}\]

D. Exam-style challenge

13Solve for the index[3 marks]

Solve \(3^x=81\).

Show Answer

Method: Rewrite matching bases where useful, apply the relevant index law to each factor, and express the final answer in its simplest form.

\[81=3^4\]

So \(3^x=3^4\), hence \(\boxed{x=4}\).

14Fractional solution[4 marks]

Solve \(16^x=8\).

Show Answer

Method: Rewrite matching bases where useful, apply the relevant index law to each factor, and express the final answer in its simplest form.

\[16=2^4,\qquad8=2^3\]\[2^{4x}=2^3\]\[4x=3\Rightarrow\boxed{x=\frac34}\]
15Negative solution[4 marks]

Solve \(9^x=\frac1{27}\).

Show Answer

Method: Rewrite matching bases where useful, apply the relevant index law to each factor, and express the final answer in its simplest form.

\[9^x=(3^2)^x=3^{2x}\]\[\frac1{27}=3^{-3}\]\[2x=-3\Rightarrow\boxed{x=-\frac32}\]
16Several laws together[5 marks]

Simplify \(\frac{12a^{-2}b^5\times3a^4b^{-1}}{6ab^2}\).

Show Answer

Coefficients:

\[\frac{12\times3}{6}=6\]

Powers of \(a\):

\[a^{-2+4-1}=a^1\]

Powers of \(b\):

\[b^{5-1-2}=b^2\]

So the simplified expression is \(\boxed{6ab^2}\).

Chapter 22 high-grade checklist

Same base first

I only add or subtract indices when the bases are the same and the operation is multiplication or division.

Coefficients separately

I simplify the numerical coefficient separately from the indexed letters.

Power of a power

I multiply indices and also raise any numerical coefficient to the outside power.

Zero and negative indices

I know \(a^0=1\) and \(a^{-n}=1/a^n\).

Fractional indices

I interpret the denominator as a root and the numerator as a power.

Exponential equations

I rewrite both sides with a common base, then equate the indices.

Chapter structure: these notes follow the two Chapter 22 subtopics in the supplied Mathematics textbook—Simplifying algebraic expressions using indices; and Using the laws of indices with numerical and algebraic expressions—while the explanations, diagrams, examples and exercises on IGCSE360 are written afresh for revision and exam preparation.
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