Chapter 11 – Ratio and proportion

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Cambridge IGCSE & O Level Mathematics
Chapter 11

Ratio and proportion

Learn to compare quantities using ratios, scale ratios reliably, divide totals into unequal shares, and recognise whether a situation uses direct or inverse proportion.

By the end of this chapter, you should be able to

  • simplify two-part and three-part ratios fully;
  • convert units before simplifying measurement ratios;
  • write ratios in the form \(1:n\), including scales;
  • use equivalent ratios to find unknown quantities;
  • divide a total quantity in a stated ratio;
  • solve direct-proportion problems using a multiplier or unitary reasoning;
  • recognise inverse proportion and divide by the multiplier when appropriate;
  • check answers for sense and consistency with the ratio or proportion.
1

Subtopic 1

Ratio

A ratio compares quantities. The order matters: \(2:5\) does not mean the same as \(5:2\). Ratios can be simplified in the same way as fractions by dividing every part by a common factor.

6 : 4

Divide both parts by 2

3 : 2

Simplifying a ratio

  1. If units are present, convert every quantity to the same unit.
  2. Find a common factor of all parts—ideally the HCF.
  3. Divide every part by the same factor.
  4. Check that no further common factor remains.
Worked example · Easy

Simplify a ratio

Simplify \(24:36\).

HCF\((24,36)=12\).

\[24:36=2:3\]

Answer: \(\boxed{2:3}\)

Worked example · Medium

Simplify a ratio with different units

Simplify 2.4 m : 60 cm.

Convert 2.4 m to centimetres:

\[2.4\text{ m}=240\text{ cm}\]\[240:60=4:1\]

Answer: \(\boxed{4:1}\)

Worked example · Medium

Three-part ratio

Simplify \(42:63:105\).

The HCF of 42, 63 and 105 is 21.

\[42:63:105=2:3:5\]

Writing a ratio in the form \(1:n\)

To make the left-hand part equal to 1, divide every part by the left-hand value.

Worked example · Medium

Write a scale as \(1:n\)

Write 8 mm : 2 km in the form \(1:n\).

Use the same unit:

\[2\text{ km}=2\,000\,000\text{ mm}\]\[8:2\,000\,000=1:250\,000\]

Answer: \(\boxed{1:250\,000}\)

Map1 cm
↔
Ground50 000 cm = 500 m
Common mistake

Do not cancel quantities with different units. Convert first. In map scales, a surprisingly large value of \(n\) is normal because centimetres on a map represent metres or kilometres on the ground.

Additional exam-focused worked example

Worked example · Exam-style

Simplify the ratio \(\frac34:\frac58\).

Step-by-step solution

Multiply both quantities by 8 to remove denominators: \[\frac34:\frac58=6:5\] Answer \(\boxed{6:5}\).

Practice: from confidence to exam-style

Work each question first, then select Show Answer to reveal the steps.

1Easy practice

Simplify 35:49.

Show Answer

Steps: Divide both by 7: \(35:49=\boxed{5:7}\).

2Easy practice

Simplify 18:24:30.

Show Answer

Steps: Divide each part by 6: \(\boxed{3:4:5}\).

3Medium practice

Simplify 75 cm : 1.5 m.

Show Answer

Steps: Convert 1.5 m to 150 cm: \(75:150=\boxed{1:2}\).

4Medium practice

Write 24:40 in the form 1:n.

Show Answer

Steps: Divide both parts by 24: \(1:40/24=\boxed{1:5/3}\) or \(1:1.667\) approximately.

5Exam-style practice

The ratio of boys to girls is 8:12. What fraction of all students are girls?

Show Answer

Steps: Total parts \(8+12=20\). Fraction girls \(\frac{12}{20}=\boxed{\frac35}\).

2

Subtopic 2

Using ratio to find an unknown quantity

Equivalent ratios are produced by multiplying or dividing every part by the same number. If one actual quantity is known, use it to find the multiplier, then apply that multiplier to the other part.

Corresponding photograph dimensions can be compared using equivalent ratios.
Corresponding photograph dimensions can be compared using equivalent ratios. Textbook diagram, Chapter 11.
Ratio25
× 4820
Worked example · Easy

Scale a ratio

The ratio of red to white paint is \(1:3\). If 4 litres of red paint are used, how much white paint is needed?

The red quantity has been multiplied by 4, so multiply the white quantity by 4.

\[1:3\quad\to\quad4:12\]

Answer: \(\boxed{12\text{ litres}}\)

Worked example · Medium

Map scale

A map uses 1 cm : 2.5 km. Two places are 6.8 cm apart on the map. Find the real distance.

\[6.8\times2.5=17\]

Answer: \(\boxed{17\text{ km}}\)

Worked example · Exam-style

Find a missing dimension

Two similar photographs have corresponding side lengths in the ratio \(3:7\). The smaller width is 12 cm. Find the corresponding larger width.

From 3 to 12, multiply by 4.

\[7\times4=28\]

Answer: \(\boxed{28\text{ cm}}\)

Quick check

If the ratio is \(2:5\), the second quantity must be \(\frac52=2.5\) times the first. Use that relationship to check your answer.

Additional exam-focused worked example

Worked example · Exam-style

In a mixture, red:blue is 5:8. If there are 3.2 litres of blue, find the red paint needed.

Step-by-step solution

One ratio part represents \(3.2\div8=0.4\) L. Red uses 5 parts: \(5\times0.4=\boxed{2.0\text{ L}}\).

Practice: from confidence to exam-style

Work each question first, then select Show Answer to reveal the steps.

1Easy practice

The ratio of pencils to pens is 4:3. There are 20 pencils. How many pens?

Show Answer

Steps: A factor of 5 turns 4 into 20, so \(3\times5=\boxed{15}\) pens.

2Easy practice

A drink uses juice:water = 2:5. How much water goes with 6 L of juice?

Show Answer

Steps: Juice was multiplied by 3: \(5\times3=\boxed{15\text{ L}}\).

3Medium practice

A map scale is 1 cm:4 km. A route measures 7.5 cm. Find its real distance.

Show Answer

Steps: \[7.5\times4=\boxed{30\text{ km}}\]

4Medium practice

Two photos have height ratio small:large = 3:8. The large photo is 40 cm tall. Find the small height.

Show Answer

Steps: One part is \(40\div8=5\) cm; small height \(3\times5=\boxed{15\text{ cm}}\).

5Exam-style practice

The ratio of adults to children is 5:7. If there are 84 children, how many people are there altogether?

Show Answer

Steps: One part is \(84\div7=12\). Adults \(5\times12=60\). Total \(60+84=\boxed{144}\).

3

Subtopic 3

Dividing a quantity in a given ratio

A ratio gives the number of equal shares. To divide a total, first find the total number of shares, then the value of one share.

100100100100100100100100

Three-step method

  1. Add the ratio parts to find the total number of shares.
  2. Divide the total quantity by the number of shares to find one share.
  3. Multiply one share by each ratio part.
Worked example · Easy

Share money in a ratio

Share $360 in the ratio \(2:3\).

Total shares: \(2+3=5\).

\[360\div5=72\]

Amounts:

\[2\times72=144,\qquad3\times72=216\]

Answer: \(\boxed{\$144\text{ and }\$216}\)

Check: \(144+216=360\).

Worked example · Medium

Three-way sharing

Share 1.8 kg in the ratio \(2:3:4\). Give each amount in grams.

Convert: \(1.8\text{ kg}=1800\text{ g}\).

Total shares: \(2+3+4=9\).

\[1800\div9=200\text{ g per share}\]\[2\times200=400,\quad3\times200=600,\quad4\times200=800\]

Answer: \(\boxed{400\text{ g},600\text{ g},800\text{ g}}\)

Worked example · Exam-style

Use one known share to find the total

Sweets are shared between A and B in the ratio \(5:2\). A receives 35 sweets. How many sweets are shared altogether?

5 shares correspond to 35 sweets.

\[35\div5=7\text{ sweets per share}\]

Total shares: \(5+2=7\).

\[7\times7=\boxed{49}\]

Additional exam-focused worked example

Worked example · Exam-style

Three friends divide $1 680 in the ratio 2:5:7. Find the difference between the largest and smallest shares.

Step-by-step solution

Total parts \(2+5+7=14\); one part \(1680\div14=120\). Largest \(7\times120=840\); smallest \(2\times120=240\). Difference \(840-240=\boxed{\$600}\).

Practice: from confidence to exam-style

Work each question first, then select Show Answer to reveal the steps.

1Easy practice

Share $240 in the ratio 1:3.

Show Answer

Steps: Four parts; one part \(240\div4=60\). Shares \(\boxed{\$60,\ \$180}\).

2Easy practice

Divide 72 sweets in the ratio 4:5.

Show Answer

Steps: Nine parts; one part \(72\div9=8\). Shares \(\boxed{32,40}\).

3Medium practice

Share 650 g in the ratio 2:3:5.

Show Answer

Steps: Ten parts; one part 65 g. Shares \(\boxed{130\text{ g},195\text{ g},325\text{ g}}\).

4Medium practice

A total of 54 pupils has boys:girls = 4:5. Find numbers of each.

Show Answer

Steps: Nine parts; one part 6 pupils. Boys \(4\times6=\boxed{24}\), girls \(5\times6=\boxed{30}\).

5Exam-style practice

A prize of $875 is shared in ratio 3:4. By how much does the larger share exceed the smaller?

Show Answer

Steps: Seven parts; one part $125. Larger $500, smaller $375; difference \(\boxed{\$125}\).

4

Subtopic 4

Proportion

Proportion describes how two quantities change together. In this chapter, the key distinction is between direct proportion and inverse proportion.

Direct proportion

Quantity A ↑Quantity B ↑

If one quantity is multiplied by a factor, the other is multiplied by the same factor.

Example: more cupcakes → more flour.

Inverse proportion

Quantity A ↑Quantity B ↓

If one quantity is multiplied by a factor, the other is divided by that factor.

Example: more workers → less time for the same job.

Direct proportion

Worked example · Easy

Use a multiplier

5 notebooks cost $12. How much do 15 notebooks cost at the same rate?

15 is 3 times 5.

\[12\times3=\boxed{\$36}\]
Worked example · Medium

Direct proportion with a non-integer multiplier

A car uses 18 litres of fuel for 144 km. Estimate the fuel needed for a similar 360 km journey.

Multiplier:

\[\frac{360}{144}=2.5\]\[18\times2.5=\boxed{45\text{ litres}}\]

Inverse proportion

Worked example · Medium

Workers and time

6 workers can complete a job in 10 days. How long would 15 workers take, assuming they all work at the same rate?

Workers are multiplied by

\[\frac{15}{6}=2.5\]

Time is divided by 2.5:

\[10\div2.5=\boxed{4\text{ days}}\]
Worked example · Exam-style

Speed and time for a fixed journey

A journey takes 54 minutes at 40 km/h. How long would the same journey take at 60 km/h?

Speed multiplier:

\[\frac{60}{40}=1.5\]

For the same distance, time is inversely proportional to speed:

\[54\div1.5=\boxed{36\text{ minutes}}\]
Worked example · Exam-style

Decide direct or inverse

8 taps fill a tank in 15 hours. How long would 12 identical taps take?

More taps means less time, so this is inverse proportion.

Multiplier in number of taps:

\[\frac{12}{8}=1.5\]\[15\div1.5=\boxed{10\text{ hours}}\]
How to decide

Ask what should happen physically. If one quantity increases, should the other also increase? That suggests direct proportion. If it should decrease for the same job, distance or supply, that suggests inverse proportion.

Additional exam-focused worked example

Worked example · Exam-style

Eight pumps empty a pool in 15 h, all working at the same rate. How long do 12 pumps need?

Step-by-step solution

For fixed work, pumps × time stays constant (inverse proportion). \[8\times15=12\times t\Rightarrow t=\frac{120}{12}=\boxed{10\text{ h}}\]

Practice: from confidence to exam-style

Work each question first, then select Show Answer to reveal the steps.

1Easy practice

3 notebooks cost $7.50. How much do 6 cost at the same price?

Show Answer

Steps: Twice as many notebooks: \(7.50\times2=\boxed{\$15.00}\).

2Easy practice

4 kg of fruit cost $18. Find the cost of 10 kg.

Show Answer

Steps: Cost per kilogram \(18\div4=\$4.50\). For 10 kg: \(4.50\times10=\boxed{\$45}\).

3Medium practice

A recipe for 5 people needs 350 g of rice. How much is needed for 8?

Show Answer

Steps: Direct proportion: \(350\times8/5=\boxed{560\text{ g}}\).

4Medium practice

6 workers complete a job in 9 days. How long for 3 equally efficient workers?

Show Answer

Steps: Inverse proportion: \(6\times9=3\times t\Rightarrow t=\boxed{18\text{ days}}\).

5Exam-style practice

A car takes 4 h at 60 km/h for a fixed journey. What constant speed is required to finish in 3 h?

Show Answer

Steps: Distance \(60\times4=240\) km. Required speed \(240\div3=\boxed{80\text{ km/h}}\).

Chapter 11 practice

Start with straightforward ratio fluency, then move into scale, sharing, direct proportion and inverse-proportion problems. Keep each answer closed until you have attempted the question.

A. Build confidence

1Simplify a ratio[2 marks]

Simplify \(42:56\).

Show Answer

HCF\((42,56)=14\).

\[42:56=3:4\]

\(\boxed{3:4}\)

2Different units[3 marks]

Simplify 1.5 kg : 450 g.

Show Answer

Convert 1.5 kg to 1500 g.

\[1500:450=10:3\]

\(\boxed{10:3}\)

3Three-part ratio[2 marks]

Simplify \(18:30:42\).

Show Answer

Divide every part by 6.

\[18:30:42=\boxed{3:5:7}\]
4Form \(1:n\)[3 marks]

Write \(4:15\) in the form \(1:n\).

Show Answer

Divide both parts by 4.

\[4:15=1:\frac{15}{4}=\boxed{1:3.75}\]

B. Equivalent ratios and sharing

5Unknown quantity[3 marks]

The ratio of boys to girls is \(3:5\). If there are 18 boys, how many girls are there?

Show Answer

3 parts become 18, so the multiplier is 6.

\[5\times6=\boxed{30}\]
6Map scale[4 marks]

A map scale is 1 cm : 4 km. Two towns are 7.5 cm apart on the map. Find the actual distance.

Show Answer
\[7.5\times4=\boxed{30\text{ km}}\]
7Share in a ratio[4 marks]

Share $540 in the ratio \(4:5\).

Show Answer

Total shares: \(4+5=9\).

\[540\div9=60\]\[4\times60=240,\qquad5\times60=300\]

\(\boxed{\$240\text{ and }\$300}\)

8Three-way sharing[5 marks]

Divide 960 g in the ratio \(2:3:7\).

Show Answer

Total shares: \(2+3+7=12\).

\[960\div12=80\text{ g}\]

Amounts:

\[160\text{ g},\ 240\text{ g},\ 560\text{ g}\]
9Known share to total[4 marks]

A and B share money in the ratio \(7:3\). A receives $189. Find the total amount shared.

Show Answer

One share:

\[189\div7=27\]

Total shares = 10.

\[10\times27=\boxed{\$270}\]

C. Proportion

10Direct proportion[4 marks]

12 metres of cable has a mass of 7.8 kg. Find the mass of 30 metres of the same cable.

Show Answer

Multiplier:

\[30\div12=2.5\]\[7.8\times2.5=\boxed{19.5\text{ kg}}\]
11Currency-style direct proportion[4 marks]

£40 is worth $52 at a fixed exchange rate. How many dollars is £150 worth?

Show Answer

Multiplier:

\[150\div40=3.75\]\[52\times3.75=\boxed{\$195}\]
12Inverse proportion[4 marks]

10 workers take 18 days to complete a job. How long would 15 workers take at the same rate?

Show Answer

Worker multiplier:

\[15\div10=1.5\]

Divide the time by 1.5:

\[18\div1.5=\boxed{12\text{ days}}\]
13Inverse proportion with a supply[4 marks]

A supply of food feeds 24 animals for 15 days. How long will the same supply feed 30 animals?

Show Answer

Animal multiplier:

\[30\div24=1.25\]\[15\div1.25=\boxed{12\text{ days}}\]

D. Exam-style challenge

14Scale in \(1:n\)[5 marks]

On a plan, 6 mm represents 1.8 m. Write the scale in the form \(1:n\).

Show Answer

Convert 1.8 m to 1800 mm.

\[6:1800=\boxed{1:300}\]
15Ratio and total[6 marks]

The ratio of red, blue and green counters is \(4:5:3\). There are 24 green counters. Find the total number of counters.

Show Answer

3 shares correspond to 24, so one share is 8.

Total shares:

\[4+5+3=12\]\[12\times8=\boxed{96}\]
16Mixture problem[6 marks]

A drink is made by mixing concentrate and water in the ratio \(2:7\). A bottle contains 1.35 litres of drink. Find the volume of concentrate in millilitres.

Show Answer

Total shares = 9.

Convert 1.35 L to 1350 ml.

\[1350\div9=150\text{ ml per share}\]\[2\times150=\boxed{300\text{ ml}}\]
17Direct or inverse?[6 marks]

At a constant speed, a machine produces 840 components in 6 hours. a) How many components will it produce in 9 hours? b) State whether this is direct or inverse proportion.

Show Answer

a) Time multiplier:

\[9\div6=1.5\]\[840\times1.5=\boxed{1260}\]

b) More time gives more output at the same rate, so it is \(\boxed{\text{direct proportion}}\).

18Fixed-distance journey[7 marks]

A journey takes 72 minutes at an average speed of 50 km/h. The same distance is travelled at 80 km/h. Find the new journey time.

Show Answer

For a fixed distance, speed and time are inversely proportional.

Speed multiplier:

\[80\div50=1.6\]\[72\div1.6=\boxed{45\text{ minutes}}\]

Chapter 11 high-grade checklist

Units first

I convert measurement ratios to the same units before simplifying.

Simplest form

I divide every part by the same common factor and check that no further simplification is possible.

Equivalent ratios

I apply exactly the same multiplier to every part of a ratio.

Sharing

I add the parts, find one share, then multiply back—and check the shares sum to the total.

Direct proportion

I multiply both quantities by the same factor.

Inverse proportion

For the same job, distance or supply, if one quantity is multiplied by a factor, I divide the other by that factor.

Chapter source: Subtopic headings match Chapter 11 of the uploaded textbook. New image files contain only original book figures, while formulas, explanations and step-by-step solutions remain selectable text.
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