Chapter 37 – Angles

← Chapter 36All chaptersChapter 38 →
Cambridge IGCSE & O Level Mathematics
Chapter 37 · Completely rewritten

Angles

Source-matched teaching notes, visual explanations, graduated worked examples and independent examination-style practice.

What you will learn

Use the key facts confidently, select an appropriate method, communicate each working step, and check the reasonableness of the final result.

  • Angles formed by straight lines
  • Angles formed within parallel lines
  • The angles in a quadrilateral
  • The angles in a polygon
1

Subtopic 1

Angles formed by straight lines

Mark the vertex and the exact angle being requested. A full turn at a point is \(360^\circ\); adjacent angles on a straight line total \(180^\circ\); vertically opposite angles formed by crossing lines are equal.

Three first-response facts

  • At a point: \(\sum\theta=360^\circ\).
  • On a straight line: adjacent angles sum to \(180^\circ\).
  • Intersecting lines: vertically opposite angles are equal.

Explain the rule in words next to your equation. Never trust the visual scale of an exam diagram, and avoid confusing neighbouring angles with opposite ones.

Several angles around one point
Original Chapter 37 textbook figure: Several angles around one point. Explanation is provided in the lesson text.
Worked examples: easy → medium → exam-style

Study the reason for each step; in an examination the method and relevant geometric explanation can earn marks even if a later calculation goes wrong.

Worked example · Easy

Missing angle around a point

Three angles around a point are \(124^\circ\), \(76^\circ\) and \(x\).

\(x=360-124-76=\boxed{160^\circ}\), angles at a point total \(360^\circ\).

Worked example · Easy

A straight line

Two adjacent angles on a line are \(3x\) and \(2x\).

\(3x+2x=180\); \(5x=180\); \(\boxed{x=36^\circ}\).

Worked example · Medium

Vertically opposite algebra

Opposite angles at an intersection are \((5x+8)^\circ\) and \((3x+44)^\circ\). Find \(x\).

Opposite angles are equal: \(5x+8=3x+44\); \(2x=36\); \(\boxed{x=18}\).

Worked example · Medium

Ratio on a straight line

Adjacent angles on a straight line are in the ratio \(4:5\). Find both.

Nine equal parts make \(180^\circ\). One part \(=20^\circ\); angles \(=\boxed{80^\circ,100^\circ}\).

Worked example · Exam-style

Four algebraic angles

Four angles around a point are \(x,2x,(x+30),(3x-20)\) degrees. Find \(x\) and the largest angle.

\(x+2x+x+30+3x-20=360\), so \(7x+10=360\), \(x=50\). Largest \(3(50)-20=\boxed{130^\circ}\).

2

Subtopic 2

Angles formed within parallel lines

A transversal crosses two parallel lines. Corresponding angles (matching corners) are equal; alternate interior angles (opposite sides inside the parallels) are equal; co-interior angles (same side inside) add to \(180^\circ\).

Angles in a triangle

The three interior angles add to \(180^\circ\). An exterior angle equals the sum of the two opposite interior angles. Isosceles triangles have equal base angles; equilateral triangles have three angles of \(60^\circ\); right-angled triangles contain \(90^\circ\).

Do not assume corresponding or alternate angles are equal unless the lines really are marked parallel. In proofs, state the correct pair of angles and the parallel-line reason.

Angles formed by a transversal and parallel lines
Original Chapter 37 textbook figure: Angles formed by a transversal and parallel lines. Explanation is provided in the lesson text.
Isosceles, equilateral and right-angle triangle diagrams
Original Chapter 37 textbook figure: Isosceles, equilateral and right-angle triangle diagrams. Explanation is provided in the lesson text.
Worked examples: easy → medium → exam-style

Study the reason for each step; in an examination the method and relevant geometric explanation can earn marks even if a later calculation goes wrong.

Worked example · Easy

Corresponding angles

Two parallel lines are crossed by a transversal; an angle of \(68^\circ\) corresponds to \(x\).

Corresponding angles are equal: \(\boxed{x=68^\circ}\).

Worked example · Easy

Co-interior angles

Co-interior angles are \(112^\circ\) and \(x\).

\(x=180-112=\boxed{68^\circ}\).

Worked example · Medium

Isosceles triangle

An isosceles triangle has vertex angle \(42^\circ\). Find each base angle.

Equal base angles each \((180-42)/2=\boxed{69^\circ}\).

Worked example · Medium

Exterior angle of a triangle

Opposite interior angles are \(46^\circ\) and \(58^\circ\). Find the exterior angle.

Exterior angle \(=46+58=\boxed{104^\circ}\).

Worked example · Exam-style

Parallel line and triangle

Triangle \(ABC\) has \(\angle A=53^\circ\), \(\angle B=72^\circ\). A line through C parallel to AB creates a corresponding angle equal to \(\angle A\). Find that angle and \(\angle C\).

Corresponding angle \(=\boxed{53^\circ}\). Triangle sum gives \(\angle C=180-53-72=\boxed{55^\circ}\).

3

Subtopic 3

The angles in a quadrilateral

The four interior angles of any quadrilateral add to \(360^\circ\). In a parallelogram, opposite angles are equal and adjacent angles add to \(180^\circ\). A rectangle has four right angles; an isosceles trapezium has equal base angles at each parallel side.

Multi-step quadrilateral problems

Identify right angles, parallel lines, equal sides or equal angles from given markings. Form an equation using \(360^\circ\) or one of the special-shape facts; then calculate, and give a reason.

Angles in a four-sided figure
Original Chapter 37 textbook figure: Angles in a four-sided figure. Explanation is provided in the lesson text.
Worked examples: easy → medium → exam-style

Study the reason for each step; in an examination the method and relevant geometric explanation can earn marks even if a later calculation goes wrong.

Worked example · Easy

Missing quadrilateral angle

Three interior angles are \(90^\circ,108^\circ,77^\circ\). Find the fourth.

\(x=360-90-108-77=\boxed{85^\circ}\).

Worked example · Easy

Parallelogram

One angle of a parallelogram is \(74^\circ\). Find its adjacent angle.

Adjacent parallelogram angles are supplementary: \(180-74=\boxed{106^\circ}\).

Worked example · Medium

Four algebraic angles

Quadrilateral angles are \(x,2x,(x+20),(2x+40)\). Find \(x\).

\(6x+60=360\), so \(\boxed{x=50}\).

Worked example · Medium

Isosceles trapezium

An isosceles trapezium has one angle of \(116^\circ\). Find the other three.

The matching angle on that base is \(116^\circ\). Each adjacent angle on a leg is \(180-116=64^\circ\). Other three: \(\boxed{116^\circ,64^\circ,64^\circ}\).

Worked example · Exam-style

Diagonal dividing a quadrilateral

A quadrilateral is divided by a diagonal. One triangle has angles \(37^\circ,65^\circ,x\); the other has \(82^\circ,45^\circ,y\). Find \(x+y\).

\(x=180-37-65=78^\circ\); \(y=180-82-45=53^\circ\). Thus \(\boxed{x+y=131^\circ}\).

4

Subtopic 4

The angles in a polygon

For any simple polygon with \(n\) sides, draw diagonals from one vertex to divide it into \(n-2\) triangles. The sum of its interior angles is therefore \((n-2)180^\circ\).

Regular polygons

For a regular \(n\)-gon, each exterior angle is \(\frac{360^\circ}{n}\); each interior angle is \(180^\circ-\frac{360^\circ}{n}\). For a convex polygon the exterior angles, one at each vertex and measured consistently, total \(360^\circ\). At a vertex, an interior angle and the adjacent exterior angle add to \(180^\circ\).

Use the total exterior-angle fact to find the number of sides of a regular polygon. An irregular polygon still has the same total interior angle sum, but its individual angles need not match.

Interior and exterior angles at a polygon vertex
Original Chapter 37 textbook figure: Interior and exterior angles at a polygon vertex. Explanation is provided in the lesson text.
Worked examples: easy → medium → exam-style

Study the reason for each step; in an examination the method and relevant geometric explanation can earn marks even if a later calculation goes wrong.

Worked example · Easy

Interior-angle sum

Find the total interior angle sum of a heptagon.

\((7-2)180=\boxed{900^\circ}\).

Worked example · Easy

Exterior angle of regular polygon

Find the exterior angle of a regular 12-gon.

\(360/12=\boxed{30^\circ}\).

Worked example · Medium

Find interior angle

Find the interior angle of a regular octagon.

Exterior \(360/8=45^\circ\), interior \(180-45=\boxed{135^\circ}\).

Worked example · Medium

Number of sides

A regular polygon has exterior angle \(18^\circ\). Find its number of sides.

\(n=360/18=\boxed{20}\).

Worked example · Exam-style

Unknown interior angle

Five angles of an irregular hexagon are \(95^\circ,112^\circ,124^\circ,137^\circ,108^\circ\). Find the sixth.

Total for six sides \(=720^\circ\). Known sum \(=576^\circ\). Missing \(=720-576=\boxed{144^\circ}\).

★

Independent practice

Exercises with step-by-step Show Answer solutions

Questions in each subtopic progress from confidence-building to developed methods and original exam-style problems. The problems are original practice, not copied past-paper questions. Answers stay closed until selected.

Angles formed by straight lines

Work through the basics first; save the examination-style questions for last.

1Question 1Basic

Two adjacent angles on a line are \(115^\circ\) and \(x\). Find \(x\).

Show Answer

Step-by-step solution: \(x=180-115=\boxed{65^\circ}\) (straight line).

2Question 2Basic

An angle vertically opposite \(73^\circ\) is \(x\). Find \(x\).

Show Answer

Step-by-step solution: Vertically opposite angles are equal: \(\boxed{x=73^\circ}\).

3Question 3Basic

Angles \(90^\circ,110^\circ\) and \(x\) meet at a point. Find \(x\).

Show Answer

Step-by-step solution: \(x=360-90-110=\boxed{160^\circ}\).

4Question 4Developing

Adjacent angles are \((2x+10)^\circ\) and \((x+20)^\circ\) on a straight line. Find \(x\).

Show Answer

Step-by-step solution: \(2x+10+x+20=180\), hence \(3x=150\), \(\boxed{x=50}\).

5Question 5Developing

Vertically opposite angles are \((4x-15)^\circ\) and \((2x+29)^\circ\). Find \(x\).

Show Answer

Step-by-step solution: \(4x-15=2x+29\); \(2x=44\); \(\boxed{x=22}\).

6Question 6Developing

Angles at a point are \(2x,3x,4x\) degrees. Find the smallest.

Show Answer

Step-by-step solution: \(9x=360\), \(x=40\); smallest \(2x=\boxed{80^\circ}\).

7Question 7Exam-style

Two adjacent angles are in ratio \(7:8\) on a straight line. Find the smaller.

Show Answer

Step-by-step solution: \(15\) parts give \(180^\circ\), each \(12^\circ\). Smaller \(7\times12=\boxed{84^\circ}\).

8Question 8Exam-style

Four angles around a point are \(3x,(2x+30),(x+15),(2x-5)\). Find \(x\).

Show Answer

Step-by-step solution: \(8x+40=360\), so \(\boxed{x=40}\).

9Question 9Exam-style

One angle at a crossing is \(138^\circ\). Find the other three.

Show Answer

Step-by-step solution: Opposite angle \(=138^\circ\). Adjacent each \(180-138=42^\circ\). Other three: \(\boxed{138^\circ,42^\circ,42^\circ}\).

Angles formed within parallel lines

Work through the basics first; save the examination-style questions for last.

10Question 10Basic

An alternate interior angle to \(82^\circ\) is \(x\). Find \(x\).

Show Answer

Step-by-step solution: Alternate angles between parallel lines are equal: \(\boxed{82^\circ}\).

11Question 11Basic

Find an angle co-interior with \(131^\circ\).

Show Answer

Step-by-step solution: \(180-131=\boxed{49^\circ}\).

12Question 12Basic

A triangle has angles \(65^\circ,45^\circ,x\). Find \(x\).

Show Answer

Step-by-step solution: \(x=180-65-45=\boxed{70^\circ}\).

13Question 13Developing

Corresponding angles are \((3x+10)^\circ\) and \((5x-30)^\circ\). Find \(x\).

Show Answer

Step-by-step solution: \(3x+10=5x-30\); \(2x=40\); \(\boxed{x=20}\).

14Question 14Developing

Co-interior angles are \((4x+12)^\circ\) and \((2x+18)^\circ\). Find \(x\).

Show Answer

Step-by-step solution: \(6x+30=180\), so \(\boxed{x=25}\).

15Question 15Developing

An equilateral triangle has one angle labelled \((2x+14)^\circ\). Find \(x\).

Show Answer

Step-by-step solution: Each angle is \(60^\circ\); \(2x+14=60\), so \(\boxed{x=23}\).

16Question 16Exam-style

An isosceles triangle has equal base angles \((3x-9)^\circ\) and a vertex angle \((2x+18)^\circ\). Find \(x\).

Show Answer

Step-by-step solution: \(2(3x-9)+2x+18=180\); \(8x=180\); \(\boxed{x=22.5}\).

17Question 17Exam-style

At a triangle vertex, the exterior angle is \(127^\circ\) and one opposite interior angle is \(68^\circ\). Find the other opposite angle.

Show Answer

Step-by-step solution: Exterior angle \(=\) sum of remote interiors, so \(127-68=\boxed{59^\circ}\).

18Question 18Exam-style

An exterior angle of a triangle is \((5x+8)^\circ\); its opposite interiors are \((2x+20)^\circ\) and \((x+42)^\circ\). Find \(x\).

Show Answer

Step-by-step solution: \(5x+8=2x+20+x+42\); \(2x=54\), hence \(\boxed{x=27}\).

The angles in a quadrilateral

Work through the basics first; save the examination-style questions for last.

19Question 19Basic

Interior angles are \(100^\circ,85^\circ,95^\circ,x\). Find \(x\).

Show Answer

Step-by-step solution: \(360-100-85-95=\boxed{80^\circ}\).

20Question 20Basic

One parallelogram angle is \(125^\circ\). Find its opposite angle.

Show Answer

Step-by-step solution: Opposite angles in a parallelogram are equal: \(\boxed{125^\circ}\).

21Question 21Basic

What is the sum of the interior angles of any quadrilateral?

Show Answer

Step-by-step solution: Divide into two triangles: \(2\times180=\boxed{360^\circ}\).

22Question 22Developing

Quadrilateral angles are \(x,2x,3x,4x\). Find \(x\).

Show Answer

Step-by-step solution: \(10x=360\), so \(\boxed{x=36^\circ}\).

23Question 23Developing

Three quadrilateral angles are \((2x+10)^\circ\), \((x+30)^\circ\) and \(100^\circ\); the fourth is \(80^\circ\). Find \(x\).

Show Answer

Step-by-step solution: \(3x+220=360\), so \(3x=140\), \(\boxed{x=46\tfrac23}\).

24Question 24Developing

Adjacent angles of a parallelogram are \((3x-15)^\circ\) and \((2x+20)^\circ\). Find \(x\).

Show Answer

Step-by-step solution: \(3x-15+2x+20=180\); \(5x=175\), \(\boxed{x=35}\).

25Question 25Exam-style

An isosceles trapezium has an upper angle \(73^\circ\). Find the two lower angles.

Show Answer

Step-by-step solution: Base angles at the upper base both \(73^\circ\). Along each leg, \(180-73=\boxed{107^\circ}\).

26Question 26Exam-style

A quadrilateral has two right angles, one angle \((4x-10)^\circ\), and the last \((2x+40)^\circ\). Find \(x\).

Show Answer

Step-by-step solution: \(90+90+4x-10+2x+40=360\); \(6x+210=360\); \(\boxed{x=25}\).

27Question 27Exam-style

A quadrilateral interior-angle ratio is \(2:3:4:6\). Find the largest.

Show Answer

Step-by-step solution: Fifteen parts sum to \(360^\circ\), so one part \(24^\circ\). Largest \(6\times24=\boxed{144^\circ}\).

The angles in a polygon

Work through the basics first; save the examination-style questions for last.

28Question 28Basic

Find the interior angle sum of a pentagon.

Show Answer

Step-by-step solution: \((5-2)180=\boxed{540^\circ}\).

29Question 29Basic

Find each exterior angle of a regular hexagon.

Show Answer

Step-by-step solution: \(360/6=\boxed{60^\circ}\).

30Question 30Basic

Find each interior angle of a regular hexagon.

Show Answer

Step-by-step solution: \(180-360/6=\boxed{120^\circ}\).

31Question 31Developing

A regular polygon has 15 sides. Find each interior angle.

Show Answer

Step-by-step solution: Exterior \(360/15=24^\circ\), interior \(180-24=\boxed{156^\circ}\).

32Question 32Developing

A regular polygon has exterior angle \(45^\circ\). Find its number of sides.

Show Answer

Step-by-step solution: \(n=360/45=\boxed{8}\).

33Question 33Developing

The interior sum of a polygon is \(1440^\circ\). Find the number of sides.

Show Answer

Step-by-step solution: \((n-2)180=1440\) gives \(n-2=8\), so \(\boxed{n=10}\).

34Question 34Exam-style

A regular polygon has interior angle \(165^\circ\). How many sides?

Show Answer

Step-by-step solution: Exterior \(180-165=15^\circ\); \(n=360/15=\boxed{24}\).

35Question 35Exam-style

A pentagon has four angles \(102^\circ,119^\circ,108^\circ,126^\circ\). Find the fifth.

Show Answer

Step-by-step solution: Total \(540^\circ\). Known sum \(455^\circ\), so fifth \(=\boxed{85^\circ}\).

36Question 36Exam-style

An irregular octagon has seven known interior angles totalling \(930^\circ\). Find the eighth.

Show Answer

Step-by-step solution: Total \((8-2)180=1080^\circ\), remaining \(1080-930=\boxed{150^\circ}\).

37Question 37Exam-style

A convex polygon has exterior angles \(30^\circ,45^\circ,65^\circ,80^\circ,70^\circ\) and one unknown. Find the unknown.

Show Answer

Step-by-step solution: Total exterior angles \(=360^\circ\). Known sum \(290^\circ\); unknown \(=\boxed{70^\circ}\).

High-grade revision checklist

Source comparison: Chapter 37, Angles, printed pages 312–322, Hodder Cambridge O Level Mathematics, Second Edition. All 4 subtopic titles match the book. Diagrams are tightly cropped source figures; prose, worked examples and practice problems are newly written.
← Chapter 36All chaptersChapter 38 →